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Copy path6.z-字形变换.js
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6.z-字形变换.js
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/*
* @lc app=leetcode.cn id=6 lang=javascript
*
* [6] Z 字形变换
*
* https://leetcode-cn.com/problems/zigzag-conversion/description/
*
* algorithms
* Medium (45.41%)
* Likes: 433
* Dislikes: 0
* Total Accepted: 69.4K
* Total Submissions: 152.6K
* Testcase Example: '"PAYPALISHIRING"\n3'
*
* 将一个给定字符串根据给定的行数,以从上往下、从左到右进行 Z 字形排列。
*
* 比如输入字符串为 "LEETCODEISHIRING" 行数为 3 时,排列如下:
*
* L C I R
* E T O E S I I G
* E D H N
*
*
* 之后,你的输出需要从左往右逐行读取,产生出一个新的字符串,比如:"LCIRETOESIIGEDHN"。
*
* 请你实现这个将字符串进行指定行数变换的函数:
*
* string convert(string s, int numRows);
*
* 示例 1:
*
* 输入: s = "LEETCODEISHIRING", numRows = 3
* 输出: "LCIRETOESIIGEDHN"
*
*
* 示例 2:
*
* 输入: s = "LEETCODEISHIRING", numRows = 4
* 输出: "LDREOEIIECIHNTSG"
* 解释:
*
* L D R
* E O E I I
* E C I H N
* T S G
*
*/
// @lc code=start
/**
* @param {string} s
* @param {number} numRows
* @return {string}
*/
var convert = function(s, numRows) {
if(numRows === 1){
return s;
}
var rows = 0;
var isDown = true;
var res = Array(numRows).fill('');
for(var i = 0; i<s.length;i++){
var curr = s[i];
res[rows] += curr;
if(rows === 0){
isDown = true
}
if(rows === numRows - 1){
isDown = false;
}
if(isDown){
rows ++;
} else {
rows --;
}
}
return res.join('');
};